An ionic solid is HCP of Q ions and P ions are in half of the tetrahedral voids. The value of should — Solid State Chemistry Question

💡 Solution & Explanation

Let the number of Q$^{2-}$ ions be $N$. The number of tetrahedral voids is $2N$. P$^{x+}$ ions occupy half of them, so their number is $\frac{1}{2} \times 2N = N$. The formula is PQ. To maintain electrical neutrality, $1(+x) + 1(-2) = 0$, so $x = 2$. Therefore, correct answer is B.