In an FCC arrangement of metallic atoms, what is the relative ratio of the sizes of tetrahedral and — Solid State Chemistry Question
Question
In an FCC arrangement of metallic atoms, what is the relative ratio of the sizes of tetrahedral and octahedral voids?
Answer: A
💡 Solution & Explanation
The ideal radius for a tetrahedral void is $r_t = 0.225R$ and for an octahedral void is $r_o = 0.414R$, where $R$ is the radius of the sphere. The ratio of their sizes is $r_t / r_o = 0.225 / 0.414 \approx 0.543$. Therefore, correct answer is A.
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