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In an FCC arrangement of metallic atoms, what is the relative ratio of the sizes of tetrahedral and Solid State Chemistry Question

Question

In an FCC arrangement of metallic atoms, what is the relative ratio of the sizes of tetrahedral and octahedral voids?

Answer: A

💡 Solution & Explanation

The ideal radius for a tetrahedral void is $r_t = 0.225R$ and for an octahedral void is $r_o = 0.414R$, where $R$ is the radius of the sphere. The ratio of their sizes is $r_t / r_o = 0.225 / 0.414 \approx 0.543$. Therefore, correct answer is A.

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