Packing fraction in FCC lattice is — Solid State Chemistry Question

💡 Solution & Explanation

In an FCC lattice, $a = \frac{4r}{\sqrt{2}}$. Packing fraction = $\frac{4 \times \frac{4}{3}\pi r^3}{a^3} = \frac{\frac{16}{3}\pi r^3}{\frac{64r^3}{2\sqrt{2}}} = \frac{16\pi \times 2\sqrt{2}}{3 \times 64} = \frac{\sqrt{2}\pi}{6}$. Therefore, correct answer is B.