Potassium has BCC structure with nearest neighbour distance () Å. Its density will be (K = 39, ) — Solid State Chemistry Question
Question
Potassium has BCC structure with nearest neighbour distance ($2.5 \times \sqrt{3}$) Å. Its density will be (K = 39, $N_A = 6 \times 10^{23}$)
Answer: D
💡 Solution & Explanation
Nearest neighbour distance = $\frac{\sqrt{3}a}{2} = 2.5\sqrt{3} \implies a = 5$ Å = $5 \times 10^{-10}$ m. Density = $\frac{2 \times 39 \times 10^{-3} \text{ kg}}{6 \times 10^{23} \times (5 \times 10^{-10})^3} = \frac{78 \times 10^{-3}}{750 \times 10^{-7}} = 1040$ kg/m$^3$. Therefore, correct answer is D.
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