The unit cell of a metallic element of atomic mass 108 and density 10.5 g/cm is a cube with edge len — Solid State Chemistry Question

💡 Solution & Explanation

Density $d = \frac{Z \times M}{N_A \times a^3}$. Substituting values: $10.5 = \frac{Z \times 108}{6.022 \times 10^{23} \times (409 \times 10^{-10})^3}$. Solving for $Z$ gives $Z \approx 4$. A cell with $Z=4$ is Face-Centred Cubic (FCC). Therefore, correct answer is A.