Sodium metal crystallizes in BCC lattice with the cell edge, Γ . What is the radius of the sodium ato β Solid State Chemistry Question
Question
Sodium metal crystallizes in BCC lattice with the cell edge, $a = 4.29$ Γ . What is the radius of the sodium atom?
Answer: A
π‘ Solution & Explanation
For a BCC lattice, $4r = \sqrt{3}a$. The radius $r = \frac{\sqrt{3} \times 4.29}{4} = \frac{1.732 \times 4.29}{4} \approx 1.86$ Γ . Therefore, correct answer is A.
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