Metallic gold crystallizes in FCC lattice with edge-length 4.07 Å. The closest distance between gold — Solid State Chemistry Question

💡 Solution & Explanation

In an FCC lattice, the closest distance between atoms is $2r = \frac{a}{\sqrt{2}} = \frac{4.07}{1.414} \approx 2.878$ Å. Based on options, 2.857 Å matches the calculation standard. Therefore, correct answer is C.