The correct information regarding a solid element (atomic radius = ) having ABCABC.... type packing — Solid State Chemistry Question

💡 Solution & Explanation

In an FCC lattice, the nearest OV to TV distance is $\frac{\sqrt{3}a}{4}$. The distance between two nearest OVs (edge center to adjacent edge center) is $\frac{a}{\sqrt{2}}$. The distance between successive close-packed layers is $\frac{a}{\sqrt{3}} = \frac{2\sqrt{2}r}{\sqrt{3}} = 2r\sqrt{\frac{2}{3}}$. The nearest TV-TV distance inside the unit cell is $a/2$, making option C incorrect. Therefore, correct answer is A,B,D.