The number of hexagonal faces that are present in a truncated octahedron is — Solid State Chemistry Question

💡 Solution & Explanation

A truncated octahedron is an Archimedean solid formed by cutting off the corners of an octahedron. It comprises 14 faces in total: 6 square faces (from the truncated corners) and 8 regular hexagonal faces (from the original triangular faces of the octahedron). Therefore, correct answer is 8.