Solid StatemediumINTEGER

X-ray diffraction shows that the unit cell edge length of NaCl is 500 pm. If the measured density ofSolid State Chemistry Question

Question

X-ray diffraction shows that the unit cell edge length of NaCl is 500 pm. If the measured density of NaCl is 2.964 g/ml, what per cent of $\text{Na}^+$ and $\text{Cl}^-$ ions must be missing?

Answer: 5

💡 Solution & Explanation

Theoretical density $d_{theo} = \frac{4 \times 58.5}{6 \times 10^{23} \times (5 \times 10^{-8})^3} = \frac{234}{6 \times 125 \times 10^{-1}} = \frac{234}{75} = 3.12 \text{ g/ml}$. The percentage of missing ions is given by $\frac{d_{theo} - d_{obs}}{d_{theo}} \times 100\% = \frac{3.12 - 2.964}{3.12} \times 100\% = \frac{0.156}{3.12} \times 100\% = 5\%$. Therefore, correct answer is 5.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry