The density of solid argon is at . If the argon atoms are assumed to be spheres of radius , the appr — Solid State Chemistry Question

💡 Solution & Explanation

Volume of 1 mole of Ar = $40 / 1.65 = 24.24 \text{ cm}^3$. Volume occupied by the atoms = $N_A \times \frac{4}{3} \pi r^3 = 6.022 \times 10^{23} \times \frac{4}{3} \pi (1.54 \times 10^{-8})^3 \approx 9.21 \text{ cm}^3$. Packing fraction = $9.21 / 24.24 = 0.38$ (38%). Thus, the empty space is $100\% - 38\% = 62\%$. Therefore, correct answer is 0062.