The radius of silicon atom is — Solid State Chemistry Question

💡 Solution & Explanation

For SiC ($Z=4$), $d = 3.2 = \frac{4 \times 40}{N_A \times a^3} \implies a \approx 4.36$ Å. Nearest distance $r_{Si} + r_C = \frac{\sqrt{3}a}{4} = \frac{1.732 \times 4.36}{4} \approx 1.88$ Å. $r_{Si} = 1.88 - r_C = 1.88 - 0.76 = 1.12$ Å. Therefore, correct answer is B.