The theoretical density of AB(s) in kg/m is — Solid State Chemistry Question

💡 Solution & Explanation

Molar mass $= 6.023y$ g. Edge length $a = 2 \times y^{1/3} \text{ nm} = 2 y^{1/3} \times 10^{-9}$ m. Theoretical density $d = \frac{Z \times M}{N_A \times a^3} = \frac{4 \times 6.023y \times 10^{-3}}{6.023 \times 10^{23} \times 8y \times 10^{-27}} = \frac{4 \times 10^{-3}}{8 \times 10^{-4}} = \frac{40}{8} = 5.0 \text{ kg/m}^3$. Therefore, correct answer is B.