The ratio of density of NaCl to that of KCl is — Solid State Chemistry Question

💡 Solution & Explanation

Density $d \propto M / a^3$. $M_{NaCl} = 58.5$, $M_{KCl} = 74.5$. $d_{NaCl} / d_{KCl} = (58.5 / 74.5) \times (a_{KCl} / a_{NaCl})^3 = (58.5 / 74.5) \times (8/7)^3 \approx 0.7852 \times 1.493 \approx 1.17$. Therefore, correct answer is B.