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Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is Electrochemistry Chemistry Question

Question

Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m^–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte (in S m^2 mol^–1) is

Answer: D

💡 Solution & Explanation

Cell constant G* = κ × R = 1.4 S m^–1 × 50 Ω = 70 m^–1. For the 0.5 M solution, specific conductance κ = G* / R = 70 / 280 = 0.25 S m^–1. Concentration C = 0.5 M = 500 mol/m^3. Molar conductivity Λ_m = κ / C = 0.25 / 500 = 5 × 10^–4 S m^2 mol^–1. Therefore, correct answer is D.

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