A volume of 100 ml of 0.6 N–CuSO4 solution is electrolysed between two platinum electrodes till the concentration in the residual liquid is 0.1 N, when a steady current of 5.0 A is used. How long shou

Question

A volume of 100 ml of 0.6 N–CuSO4 solution is electrolysed between two platinum electrodes till the concentration in the residual liquid is 0.1 N, when a steady current of 5.0 A is used. How long should the current be passed to get the above change?

Prashant Kotian · Accepted Answer

Correct answer: A. Initial equivalents of CuSO4 = 0.6 N × 0.1 L = 0.06 eq. Final equivalents = 0.1 N × 0.1 L = 0.01 eq. Change in equivalents = 0.06 - 0.01 = 0.05 eq. Total charge required (Q) = 0.05 × 96500 C = 4825 C. Using Q = I × t, time t = 4825 / 5.0 = 965 s. Therefore, correct answer is A.

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