The minimum mass of NaOH required to be added in RHS to consume all the H^+ present in RHS of the ce — Electrochemistry Chemistry Question

💡 Solution & Explanation

The oxidation potential of the anode is E_anode = -0.76 + (0.06/2) * log(0.01) = -0.76 - 0.06 = -0.82 V. The cell EMF is E_cell = E_cathode - E_anode = (-0.06 * pH) - (-0.82) = 0.82 - 0.06 * pH. Given E_cell = 0.70 V, we have 0.70 = 0.82 - 0.06 * pH, which gives 0.06 * pH = 0.12, so pH = 2. Thus, [H^+] = 10^-2 M = 0.01 M. In 500 mL (0.5 L), moles of H^+ = 0.01 * 0.5 = 0.005 mol. Mass of NaOH required = 0.005 mol * 40 g/mol = 0.2 g. Therefore, correct answer is C.