The standard reduction potential at 25°C of the reaction 2H2O + 2e^– H2 + 2OH^– is –0.84 V. Calculate equilibrium constant for the reaction: 2H2O H3O^+ + OH^– at 25°C. (2.303RT/F = 0.06)

Question

The standard reduction potential at 25°C of the reaction 2H2O + 2e^– <=> H2 + 2OH^– is –0.84 V. Calculate equilibrium constant for the reaction: 2H2O <=> H3O^+ + OH^– at 25°C. (2.303RT/F = 0.06)

Prashant Kotian · Accepted Answer

Correct answer: A. The given half-reaction standard potential relates to Kw. Utilizing E° = (0.06/n) * log(K) for the full cell consisting of water reduction and hydrogen oxidation gives -0.84 = (0.06/1) * log(Kw). Solving for log(Kw) gives -14, meaning Kw = 10^-14. Therefore, correct answer is A.

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