The EMFs of the cell obtained by combining separately Zn and Cu electrodes of a Daniel cell with nor β Electrochemistry Chemistry Question
Question
The EMFs of the cell obtained by combining separately Zn and Cu electrodes of a Daniel cell with normal calomel electrodes are 1.083 V and β0.018 V, respectively, at 25Β° C. If the potential of normal calomel electrode is β0.28 V, the EMF of the Daniel cell is
Answer: B
π‘ Solution & Explanation
The potential difference combinations given correspond to E1 = E_NCE - E_Zn = 1.083 V and E2 = E_NCE - E_Cu = -0.018 V. The EMF of the Daniel cell is E_Cu - E_Zn, which can be found by evaluating E1 - E2 = 1.083 - (-0.018) = 1.101 V. Therefore, correct answer is B.
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