The EMF of cell: H2(g) \| Buffer \|\| Normal calomel electrode, is 0.70 V at 25°C, when barometric pressure is 760 mm. What is the pH of the buffer solution? E°_Calomel = 0.28 V. [2.303RT/F = 0.06]

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Prashant Kotian · Accepted Answer

Correct answer: B. E_cell = E_cathode - E_anode = E_Calomel - E_H2. Substituting the expressions gives 0.70 = 0.28 - (-0.06 * pH) = 0.28 + 0.06 * pH. Solving for pH gives 0.06 * pH = 0.42, which results in pH = 7.0. Therefore, correct answer is B.

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