The EMF of the cell: Zn–Hg(C1M) \| Zn^2+(aq) \| Zn–Hg (C2M) at 25°C, if the concentrations of the zi — Electrochemistry Chemistry Question
Question
The EMF of the cell: Zn–Hg(C1M) \| Zn^2+(aq) \| Zn–Hg (C2M) at 25°C, if the concentrations of the zinc amalgams are: C1 = 10 g per 100 g of mercury, C2 = 1 g per 100 g mercury, is
Answer: B
💡 Solution & Explanation
This is a concentration cell with amalgam electrodes. The formula for EMF is E_cell = (0.0591/n) * log(C1/C2). Here, n = 2 for Zn, C1 = 10, and C2 = 1. E_cell = (0.0591/2) * log(10/1) = 0.02955 V. Therefore, correct answer is B.
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