The potential (EMF) of a cell consisting of an anode of silver in 0.10 M – AgNO3 solution and a cathode of Pt immersed in a solution of 1.6 M – Cr2O7^2–, 0.4 M – Cr^3+ and 0.1 M – H^+ is (E°_Ag+\|Ag =

Question

The potential (EMF) of a cell consisting of an anode of silver in 0.10 M – AgNO3 solution and a cathode of Pt immersed in a solution of 1.6 M – Cr2O7^2–, 0.4 M – Cr^3+ and 0.1 M – H^+ is (E°_Ag+\|Ag = 0.80 V and E°_Cr2O7^2–\|Cr3+ = 1.33 V)

Prashant Kotian · Accepted Answer

Correct answer: A. Anode: Ag -> Ag^+ + e^-; E_a = 0.80 + 0.059*log(0.1) = 0.74 V. Cathode: Cr2O7^2- + 14H^+ + 6e^- -> 2Cr^3+ + 7H2O. E_c = 1.33 - (0.06/6)*log([Cr^3+]^2 / ([Cr2O7^2-][H^+]^14)) = 1.33 - 0.01*log(0.16 / (1.6 * 10^-14)) = 1.33 - 0.01*log(10^13) = 1.33 - 0.13 = 1.20 V. E_cell = 1.20 - 0.74 = 0.46 V. Therefore, correct answer is A.

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