The overall formation constant for the reaction of 6 mole of CN^– with cobalt (II) is 1 × 10^19. What is the formation constant for the reaction of 6 moles of CN^– with cobalt (III)? Given that Co(CN)

Question

The overall formation constant for the reaction of 6 mole of CN^– with cobalt (II) is 1 × 10^19. What is the formation constant for the reaction of 6 moles of CN^– with cobalt (III)? Given that Co(CN)6^3– + e^– -> Co(CN)6^4– ; E° = –0.83 V and Co^3+ + e^– -> Co^2+; E° = +1.81 V and 2.303RT/F = 0.06.

Prashant Kotian · Accepted Answer

Correct answer: A. Using the relationship between standard potentials and formation constants: E°_Co3+/Co2+ + (0.06/1) * log(Kf_Co2+) = E°_complex + (0.06/1) * log(Kf_Co3+). Plugging in the given values: 1.81 - (-0.83) = 0.06 * log(Kf_Co3+ / 10^19). 2.64 = 0.06 * log(Kf_Co3+ / 10^19). log(Kf_Co3+/10^19) = 44, which means Kf_Co3+ = 10^44 * 10^19 = 10^63. Therefore, correct answer is A.

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