The current of 9.65 A flowing for 10 min deposits 3.0 g of a metal. The equivalent weight of the met — Electrochemistry Chemistry Question

💡 Solution & Explanation

Total charge $Q = I \times t = 9.65 \times (10 \times 60) = 5790$ C. According to Faraday's law: $m = (E/96500) \times Q$. $3.0 = (E / 96500) \times 5790 \Rightarrow E = (3.0 \times 96500) / 5790 = 50$. Therefore, correct answer is C.