When 12,000 coulombs of electricity is passed through the electrolyte, 3.0 g of a metal of atomic ma — Electrochemistry Chemistry Question

💡 Solution & Explanation

Using Faraday's Law: $m = (M/n) \times Q / 96500$. $3.0 = (96.5 / n) \times (12000 / 96500)$. $3.0 = 12000 / (1000 \times n) = 12 / n$. Solving for $n$ gives $n = 12 / 3 = 4$. Since it's a cation being reduced, its valency is +4. Therefore, correct answer is A.