An electrolytic cell contains a solution of Ag2SO4 and platinum electrodes. A current is passed unti — Electrochemistry Chemistry Question

💡 Solution & Explanation

Moles of O2 = 1.6 / 32 = 0.05 mol. O2 evolution involves 4e- per molecule, so total equivalents = $0.05 \times 4 = 0.2$ eq. Equivalents of Ag deposited must also be 0.2. Since Ag is +1, moles of Ag = 0.2. Mass = $0.2 \times 108 = 21.6$ g. Therefore, correct answer is D.