Electrolysis of a solution of HSO4– ions produces S2O8^2–. Assuming 75% current efficiency, what cur — Electrochemistry Chemistry Question
Question
Electrolysis of a solution of HSO4– ions produces S2O8^2–. Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S2O8^2– per hour?
Answer: A
💡 Solution & Explanation
Reaction: $2HSO_4^- \rightarrow S_2O_8^{2-} + 2H^+ + 2e^-$. 1 mole $S_2O_8^{2-}$ needs 2F of charge. Required charge per hour = $2 \times 96500 = 193000$ C. Theoretical current = $193000 / 3600 = 53.6$ A. Given 75% efficiency, actual current = $53.6 / 0.75 \approx 71.5$ A. Therefore, correct answer is A.
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