Three faradays of electricity is passed through molten Al2O3, aqueous solutions of CuSO4 and molten — Electrochemistry Chemistry Question

💡 Solution & Explanation

3 F provides 3 moles of electrons. Al is +3 (requires 3F/mol $\rightarrow$ 1 mol deposited). Cu is +2 (requires 2F/mol $\rightarrow$ 1.5 mol deposited). Na is +1 (requires 1F/mol $\rightarrow$ 3 mol deposited). The molar ratio is 1 : 1.5 : 3. Therefore, correct answer is C.