In the lead storage battery, the anode reaction is Pb(s) + HSO4– + H2O PbSO4(s) + H3O+ + 2e–. How ma — Electrochemistry Chemistry Question

💡 Solution & Explanation

Total charge $Q = It = 1 \text{ A} \times 100 \times 3600 \text{ s} = 360000$ C. Moles of $e^- = 360000 / 96500 = 3.73$ mol. The reaction shows 1 mol Pb releases 2 mol $e^-$, so moles of Pb = $3.73 / 2 = 1.865$ mol. Mass of Pb = $1.865 \times 208 \approx 388$ g. Therefore, correct answer is B.