On passing electricity through dilute H2SO4 solution, the mass of substances liberated at the cathod — Electrochemistry Chemistry Question

💡 Solution & Explanation

Electrolysis of dilute H2SO4 yields H2 at the cathode and O2 at the anode. By Faraday's laws, equal equivalents of products are liberated. The equivalent weight of H is 1 and that of O is 8. Thus, the mass ratio of H2 to O2 is 1:8. Therefore, correct answer is A.