The current efficiency of an electrodeposition of copper metal in which 9.8 g of copper is deposited — Electrochemistry Chemistry Question

💡 Solution & Explanation

Theoretical mass = $ZIt = (E/96500) \times I \times t = (31.75 / 96500) \times 3 \times 10000 \approx 9.87$ g. Current efficiency = (Actual mass / Theoretical mass) $\times 100 = (9.8 / 9.87) \times 100 \approx 99.3\%$, which is closest to 99%. Therefore, correct answer is B.