A certain current liberated 0.50 g of hydrogen in 2 h. How many grams of copper can be liberated by — Electrochemistry Chemistry Question

💡 Solution & Explanation

According to Faraday's Second Law: $W_{Cu} / W_{H_2} = E_{Cu} / E_{H_2}$. The equivalent weight of H2 is 1, and for Cu in CuSO4 it is 63.5 / 2 = 31.75. Thus, $W_{Cu} / 0.50 = 31.75 / 1$. $W_{Cu} = 31.75 \times 0.50 = 15.875 \approx 15.88$ g. Therefore, correct answer is B.