A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of M h — Electrochemistry Chemistry Question

💡 Solution & Explanation

In a concentration cell of hydrogen electrodes, the negative electrode is the anode, so $[H^+]_{anode} = 10^{-6}$ M. The cell potential is given by $E_{cell} = 0.0591 \log \frac{[H^+]_{cathode}}{[H^+]_{anode}}$. Thus, $0.118 = 0.0591 \log \frac{[H^+]_{cathode}}{10^{-6}}$, which simplifies to $\log \frac{[H^+]_{cathode}}{10^{-6}} = 2$. Solving this gives $[H^+]_{cathode} / 10^{-6} = 10^2$, meaning $[H^+]_{cathode} = 10^{-4}$ M. Therefore, correct answer is C.