For the cell reaction: ; V. The value of at 298 K is [] — Electrochemistry Chemistry Question

💡 Solution & Explanation

From the relationship $\log K_c = \frac{n E^\circ}{0.06}$, where $n$ is the number of transferred electrons (which is 4 for this reaction), we have $\log K_c = \frac{4 \times 0.18}{0.06} = \frac{0.72}{0.06} = 12$. Therefore, correct answer is A.