For the electrochemical cell, , V and V. From this data, one can deduce that — Electrochemistry Chemistry Question
Question
For the electrochemical cell, $M \| M^+ \|\| X^- \| X$, $E^\circ_{M^+\|M} = 0.44$ V and $E^\circ_{X\|X^-} = 0.33$ V. From this data, one can deduce that
Answer: B
💡 Solution & Explanation
The standard reduction potential of $M^+$ to $M$ is +0.44 V, and the standard reduction potential of $X$ to $X^-$ is +0.33 V. For the reaction $M^+ + X^- \rightarrow M + X$, the cell potential is $E^\circ_{cathode} - E^\circ_{anode} = E^\circ_{M^+\|M} - E^\circ_{X\|X^-} = 0.44 - 0.33 = +0.11$ V. Since $E^\circ$ is positive, this reaction is spontaneous. Therefore, correct answer is B.
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