ElectrochemistrymediumMCQ SINGLE

Calculate (in ) for SrCl2 at 25°C, from the following data:<br>Conc.: 0.25 M, 1.0 M<br> (in ): 260, Electrochemistry Chemistry Question

Question

Calculate $\Lambda_m^\circ$ (in $\Omega^{–1}\text{ cm}^2\text{ mol}^{–1}$) for SrCl2 at 25°C, from the following data:<br>Conc.: 0.25 M, 1.0 M<br>$\Lambda_m$ (in $\Omega^{–1}\text{ cm}^2\text{ mol}^{–1}$): 260, 250

Answer: A

💡 Solution & Explanation

Using the Debye-Hückel-Onsager equation $\Lambda_m = \Lambda_m^\circ - A\sqrt{C}$. For 0.25 M, $\sqrt{C} = 0.5$, so $260 = \Lambda_m^\circ - 0.5A$. For 1.0 M, $\sqrt{C} = 1.0$, so $250 = \Lambda_m^\circ - 1.0A$. Subtracting the second from the first gives $10 = 0.5A \Rightarrow A = 20$. Then $\Lambda_m^\circ = 250 + 20(1.0) = 270$. Therefore, correct answer is A.

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