Equal volumes of 0.015 M – CH3COOH and 0.015 M – NaOH solutions are mixed together. What would be th — Electrochemistry Chemistry Question
Question
Equal volumes of 0.015 M – CH3COOH and 0.015 M – NaOH solutions are mixed together. What would be the molar conductivity of mixture if conductivity of CH3COONa is $6.3 \times 10^{–4}\text{ S cm}^{–1}$?
Answer: C
💡 Solution & Explanation
Mixing equal volumes halves the concentration of the resulting salt. Concentration of CH3COONa = $0.015 / 2 = 0.0075\text{ M}$. Molar conductivity $\Lambda_m = (\kappa \times 1000) / C = (6.3 \times 10^{–4} \times 1000) / 0.0075 = 0.63 / 0.0075 = 84\text{ S cm}^2\text{mol}^{–1}$. Therefore, correct answer is C.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes