ElectrochemistrymediumMCQ SINGLE

Equal volumes of 0.015 M – CH3COOH and 0.015 M – NaOH solutions are mixed together. What would be thElectrochemistry Chemistry Question

Question

Equal volumes of 0.015 M – CH3COOH and 0.015 M – NaOH solutions are mixed together. What would be the molar conductivity of mixture if conductivity of CH3COONa is $6.3 \times 10^{–4}\text{ S cm}^{–1}$?

Answer: C

💡 Solution & Explanation

Mixing equal volumes halves the concentration of the resulting salt. Concentration of CH3COONa = $0.015 / 2 = 0.0075\text{ M}$. Molar conductivity $\Lambda_m = (\kappa \times 1000) / C = (6.3 \times 10^{–4} \times 1000) / 0.0075 = 0.63 / 0.0075 = 84\text{ S cm}^2\text{mol}^{–1}$. Therefore, correct answer is C.

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