How does the electrical conductivity of 20 ml of 0.2 M – MgSO4 change when 0.5 M – Ba(OH)2 solution — Electrochemistry Chemistry Question

💡 Solution & Explanation

Initially, MgSO4 provides mobile ions. As Ba(OH)2 is added, it forms BaSO4 and Mg(OH)2, which are both precipitates. This removes ions from the solution, decreasing conductivity until the equivalence point. After the equivalence point, excess Ba(OH)2 adds highly mobile $OH^-$ and $Ba^{2+}$ ions, causing the conductivity to increase. Therefore, correct answer is D.