The resistance of 1 M – CH3COOH solution is 250 , when measured in a cell of cell constant 125 m. Th — Electrochemistry Chemistry Question

💡 Solution & Explanation

Specific conductance $\kappa = G^* / R = 125 / 250 = 0.5\ \Omega^{–1}\text{m}^{–1}$. Concentration $C = 1\text{ M} = 1000\text{ mol/m}^3$. Molar conductivity $\Lambda_m = \kappa / C = 0.5 / 1000 = 5 \times 10^{–4}\ \Omega^{–1}\text{m}^2\text{mol}^{–1}$. Therefore, correct answer is A.