The specific conductance of AgCl solution in water was determined to be at 298 K. The molar conducta — Electrochemistry Chemistry Question
Question
The specific conductance of AgCl solution in water was determined to be $1.8 \times 10^{-6} \text{ }\Omega^{-1}\text{cm}^{-1}$ at 298 K. The molar conductances at infinite dilution, of $Ag^+$ and $Cl^-$ are 67.9 and $82.1 \text{ }\Omega^{-1}\text{cm}^2\text{mol}^{-1}$, respectively. What is the solubility of AgCl in water?
Answer: C
💡 Solution & Explanation
Molar conductance of AgCl at infinite dilution $\Lambda^\circ_m = 67.9 + 82.1 = 150 \text{ }\Omega^{-1}\text{cm}^2\text{mol}^{-1}$. Solubility $S = (\kappa \times 1000) / \Lambda^\circ_m$. Substituting the values: $S = (1.8 \times 10^{-6} \times 1000) / 150 = 1.8 \times 10^{-3} / 150 = 1.2 \times 10^{-5}$ M. Therefore, correct answer is C.
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