Element A (atomic mass = 112) and element B (atomic mass = 27) form chlorides. Solutions of these ch — Electrochemistry Chemistry Question
Question
Element A (atomic mass = 112) and element B (atomic mass = 27) form chlorides. Solutions of these chlorides are electrolysed separately and it is found that when the same quantity of electricity is passed, 5.6 g of A was deposited while only 0.9 g of B was deposited. The valency of B is 3. The valency of A is
💡 Solution & Explanation
Equivalent weight of B = $27 / 3 = 9$. Equivalents of B deposited = $0.9 / 9 = 0.1$ eq. By Faraday's second law, equivalents of A deposited = 0.1 eq. Equivalent weight of A = $5.6 / 0.1 = 56$. Valency of A = Atomic mass / Equivalent weight = $112 / 56 = 2$. Therefore, correct answer is B.