If a current of 1.0 A is drawn from the Daniel cell for 96.5 min, the cathode will gain in weight by — Electrochemistry Chemistry Question

💡 Solution & Explanation

Charge $Q = I \times t = 1.0 \times (96.5 \times 60) = 5790$ C. Number of Faradays = $5790 / 96500 = 0.06$ F. In a Daniel cell, Cu is deposited at the cathode: $Cu^{2+} + 2e^- \rightarrow Cu$. Moles of Cu deposited = $0.06 / 2 = 0.03$ mol. Weight gained = $0.03 \times 63.5 = 1.905$ g. Therefore, correct answer is A.