Ionic conductance at infinite dilution of Al^3+ and SO4^2– ions are 60 and 80 Ω^–1 cm^2 eq^–1, respe — Electrochemistry Chemistry Question

💡 Solution & Explanation

The equivalent conductance of a salt at infinite dilution is the simple sum of the equivalent conductances of its constituent ions: Λ°_eq = λ°_eq(Al^3+) + λ°_eq(SO4^2–) = 60 + 80 = 140 Ω^–1 cm^2 eq^–1 (Option B is correct). For Al2(SO4)3, the total cationic charge (the n-factor) is 2 × 3 = 6. The relationship between molar and equivalent conductance is Λ°_m = n-factor × Λ°_eq. Thus, Λ°_m = 6 × 140 = 840 Ω^–1 cm^2 mol^–1 (Option C is correct). Therefore, correct answer is B,C.