The temperature coefficient of the cell: is . The entropy change (in J/K) accompanying this reaction — Electrochemistry Chemistry Question
Question
The temperature coefficient of the cell: $Zn \| ZnCl_2 \| AgCl(s) \| Ag$ is $+0.001 \text{ V/K}$. The entropy change (in J/K) accompanying this reaction, at 298 K is
Answer: 0193
💡 Solution & Explanation
The overall cell reaction is $Zn(s) + 2AgCl(s) \rightarrow Zn^{2+}(aq) + 2Cl^-(aq) + 2Ag(s)$, which transfers $n = 2 electrons$. The entropy change is given by $\Delta S = n F (\partial E/\partial T)$. Substituting the values: $\Delta S = 2 \times 96500 \text{ C/mol} \times (+0.001 \text{ V/K}) = 193$ J/K. Therefore, correct answer is 0193.
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