2Ag^+ + C6H12O6 + H2O -> 2Ag(s) + C6H12O7 + 2H^+. Find ln K of this reaction. — Electrochemistry Chemistry Question
Question
2Ag^+ + C6H12O6 + H2O -> 2Ag(s) + C6H12O7 + 2H^+. Find ln K of this reaction.
Answer: B
💡 Solution & Explanation
The overall standard cell potential E°_cell = E°_red(cathode) + E°_ox(anode) = 0.80 V + (-0.05 V) = 0.75 V. The standard free energy change is related to the equilibrium constant by ln K = (nFE°)/RT = n × E° × (F/RT). The number of electrons transferred (n) is 2. Substituting the values: ln K = 2 × 0.75 × 38.92 = 1.5 × 38.92 = 58.38. Therefore, correct answer is B.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes