At the end of the electrolysis, how many grams of the gaseous product appear at the anode? — Electrochemistry Chemistry Question

💡 Solution & Explanation

The gaseous product at the anode is oxygen (O2) from the oxidation of water. The total charge passed is 54,000 C. Number of Faradays = 54,000 / 96,500 = 0.5596 F. The oxidation of water to O2 involves 4 electrons (4 Faradays per mole of O2). Moles of O2 = 0.5596 / 4 = 0.1399 mol. Mass of O2 = 0.1399 mol × 32 g/mol ≈ 4.48 g. Therefore, correct answer is A.