How much of nickel is plated on the cathode per hour? — Electrochemistry Chemistry Question

💡 Solution & Explanation

Total charge passed in one hour (3600 s) is Q = 15.0 A × 3600 s = 54,000 C. The current efficiency for Ni is 60%, so effective charge for Ni = 0.60 × 54,000 = 32,400 C. Number of Faradays = 32,400 / 96,500 = 0.33575 F. Since Ni2+ requires 2 moles of electrons per mole of Ni, moles of Ni deposited = 0.33575 / 2 = 0.167875 mol. Mass of Ni = 0.167875 × 58.7 = 9.85 g. Therefore, correct answer is D.