Conductivity of water (in Ω^–1 cm^–1) is — Electrochemistry Chemistry Question

💡 Solution & Explanation

Using the cell constant G* determined in the previous step (0.4 cm^-1), the specific conductivity (κ) of the pure pool water can be found from its resistance (R = 10,000 Ω). κ_water = G* / R = 0.4 / 10,000 = 0.00004 Ω^–1 cm^–1. Therefore, correct answer is D.