Cell constant of the conductivity cell is — Electrochemistry Chemistry Question

💡 Solution & Explanation

For the 0.02 M KCl solution, molar conductivity Λ = 200 Ω^–1 cm^2 mol^–1. Specific conductance κ = (Λ × C) / 1000 = (200 × 0.02) / 1000 = 0.004 Ω^–1 cm^–1. The cell constant G* is given by G* = κ × R = 0.004 Ω^–1 cm^–1 × 100 Ω = 0.4 cm^–1. Therefore, correct answer is B.