Read the Assertion and Reason below and choose the correct option. — Electrochemistry Chemistry Question

💡 Solution & Explanation

In Kolbe's electrolysis of aqueous sodium acetate, the cathode reaction produces exactly 1 mole of H2 gas per 2 Faradays. The anode reaction (2CH3COO^– -> C2H6 + 2CO2 + 2e^–) produces 1 mole of ethane and 2 moles of CO2 (a total of 3 moles of gas) per 2 Faradays. The ratio is 1:3, making Statement I true. Statement II is also true regarding the species discharged, but identifying the discharging species does not explain the stoichiometric 1:3 ratio. Therefore, correct answer is B.